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yksoft1

编程实现 画心形,古董 WordBasic 实现

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  •   yksoft1 · Dec 22, 2014 · 3994 views
    This topic created in 4245 days ago, the information mentioned may be changed or developed.
    看了 知乎 上这个主题 如何用C语言画一个“心形”?(http://www.zhihu.com/question/20187195),我觉得很有意思
    作为abandonware专家 我自然也弄了一个 实现了微积分书上那个最简单的笛卡尔心形
    用的是WordBasic,Word for Windows 1.0-7.0时期Word支持的脚本语言,8.0之后被基于VB5的VBA取代。
    使用了Win16的API,在32位的Word 6.0或者7.0上跑要自己修改。。
    'API函数声明
    Declare Function GetFocus Lib "user"() As Integer
    Declare Function GetDC Lib "user"(hwnd As Integer) As Integer
    Declare Function ReleaseDC Lib "user"(hwnd As Integer, hdc As Integer) As Integer
    Declare Function MoveTo Lib "gdi"(hdc As Integer, x As Integer, y As Integer) As Integer
    Declare Function LineTo Lib "gdi"(hdc As Integer, x As Integer, y As Integer) As Integer
    Declare Function SetPixel Lib "gdi"(hdc As Integer, x As Integer, y As Integer, color As Long) As
    Integer
    Declare Function FloodFill Lib "gdi"(hdc As Integer, x As Integer, y As Integer, rgb As Long) As
    Integer
    Declare Function CreatePen Lib "gdi"(style As Integer, width As Integer, rgb As Long) As Integer
    Declare Function CreateSolidBrush Lib "gdi"(rgb As Long) As Integer
    Declare Function CreateHatchBrush Lib "gdi"(type As Integer, rgb As Long) As Integer

    Declare Function SelectObject Lib "gdi"(hdc As Integer, hobj As Integer) As Integer
    Declare Function DeleteObject Lib "gdi"(hobj As Integer) As Integer
    '因为WordBasic没有数学库,就自己写了个简单的泰勒展开sin和cos,但是在这个环境下实在太慢了
    Function tsin(x)
    a = 1 : b = 1 : i = 1 : s = 0
    a = x
    tl:
    s = s +(a / b)
    a = - 1 * a * x * x
    b = b * 2 * i *(2 * i + 1)
    i = i + 1
    If a / b >= 0.005 Or a / b <= - 0.005 Then Goto tl
    tsin = s
    End Function
    Function tcos(x)
    s = 1 : t = 1 : f = 1 : v = 1 : i = 2
    While t > 0.005 Or t < - 0.005
    f = f *(- 1 * x * x)
    v = v *((i - 1) * i)
    i = i + 2
    t = f / v
    s = s + t
    Wend
    tcos = s
    End Function
    Sub MAIN
    hw = getfocus
    hd = getdc(hw)
    hp = createpen(0, 6, 255 * 65536)
    hpo = selectobject(hd, hp)
    '生成笛卡尔心形线
    r = moveto(hd, 200 + 50 *(2 * tsin(0) - tsin(0)), 100 - 50 *(2 * tcos(0) - tcos(0)))
    For i = 1 To 314
    ty = 100 - 50 *(2 * tcos(i / 50) - tcos(i / 25))
    tx = 200 + 50 *(2 * tsin(i / 50) - tsin(i / 25))
    'Print Str$(tx) + " " + Str$(ty)
    r = lineto(hd, tx, ty)
    Next
    hbr = createhatchbrush(5, 224 * 65536 + 64 * 256 + 64)
    hobr = selectobject(hd, hbr)
    r = floodfill(hd, tx, ty + 8, 255 * 65536)
    r = selectobject(hd, hobr)
    r = selectobject(hd, hpo)
    r = deleteobject(hp)
    r = deleteobject(hbr)
    r = releasedc(0, hd)
    End Sub

    运行截图x2
     
    openroc
        1
    openroc  
       Dec 22, 2014
    关于这个心形‘背后的故事,更有意思。:)
    shense
        2
    shense  
       Dec 23, 2014
    @openroc 那个逼格矿泉水百岁山的广告创意,传说就来源于这个公式背后的故事。
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