a = 0.9987623
# 将 a 保留两位小数得到
a = 0.99
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This topic created in 2999 days ago, the information mentioned may be changed or developed.
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zh0408Aug 22, 2018
1
round()
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gnozixAug 22, 2018
2
format
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4
>>> r = lambda f: f - f % 0.01
>>> r(2.368) 2.36 >>> r(2.36888888) 2.36 >>> r(2.323) 2.32 >>> r(2.326) 2.32 摘自： https://www.reddit.com/r/learnpython/comments/4nj5gu/how_to_get_float_to_two_decimal_places_without/ |
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5
int(a*100)/100
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lxy42Aug 22, 2018
6
Q. In a fixed-point application with two decimal places, some inputs have many places and need to be rounded. Others are not supposed to have excess digits and need to be validated. What methods should be used?
A. The quantize() method rounds to a fixed number of decimal places. If the Inexact trap is set, it is also useful for validation: >>> >>> TWOPLACES = Decimal(10) ** -2 # same as Decimal('0.01') >>> >>> # Round to two places >>> Decimal('3.214').quantize(TWOPLACES) Decimal('3.21') |
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pyseAug 23, 2018
8
你们的为什么没有四舍五入呢？？？
>>> a = 0.9987623 >>> print("%.2f" %a) 1.00 |
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