ideno's recent timeline updates ideno's recent timeline updates |
idenoV2EX member #143740, joined on 2015-10-21 20:13:23 +08:00Today's activity rank 29802 |
| SightRead, vibe coding 时代代码视觉增强辅助阅读插件 程序员 • ideno • 9 days ago |
| 非邪道官方订阅 A\保姆级教程的视频合集 国内原来是严格不让发的 程序员 • ideno • Jun 29 |
ideno's recent replies
1 day ago Replied to a topic by chunchun1028 › ☕Vibe Coding🤖 › 大家在等 AI 干活时，都在干些什么？ |
@lizhesystem 啊哈哈，我就是冥想
2 days ago Replied to a topic by formulahendry › Visual Studio Code › Code Runner for VS Code 发布十周年了，下载量突破 8000 万 |
厉害了老哥
Sep 15, 2025 Replied to a topic by capgrey › 输入法 › 想入门双拼，却卡在了方案选择 |
我也用的小鹤..
Jul 22, 2025 Replied to a topic by yunchuanwu › 程序员 › Trae 耍猴 |
就像纯银老哥说的, 大公司纯投入, 没见 10 倍增长, 不出几个季度就要撤了. 看来 trae 也是了
Jan 28, 2021 Replied to a topic by bytesfold › Python › 自动化脚本按步骤执行 12345，如果 4 失败想回到 2，有哪些实现方法 |
int nProc = 0;
while (true) {
swith(nProc) {
case 0: doProc0();
case 1: doProc1();
case 2: doProc2();
case 3: doProc3();
case 4: if(!doProc4()) {nProc=2; continue;}
}
break;
}
@freelancher 说的大概这么个意思(不是正确语法)
while (true) {
swith(nProc) {
case 0: doProc0();
case 1: doProc1();
case 2: doProc2();
case 3: doProc3();
case 4: if(!doProc4()) {nProc=2; continue;}
}
break;
}
@freelancher 说的大概这么个意思(不是正确语法)
Jan 28, 2021 Replied to a topic by wxVIP › Linux › 求助 在 Linux shell 里的替换问题 |
echo 'AdadaBdaC' | awk '{str=tolower($0);printf("%s-%s-%s", substr(str, 1, 5), substr(str, 6, 3), substr(str, 9));}'
Jan 28, 2021 Replied to a topic by wxVIP › Linux › 求助 在 Linux shell 里的替换问题 |
echo 'AdadaBdaC' | awk '{first=tolower(substr($0, 1, 5)); second=tolower(substr($0, 6, 3)); third=tolower(substr($0, 9)); printf("%s-%s-%s", first, second, third);}'
Mar 24, 2020 Replied to a topic by jackal › Vim › 如何卸载/删除 Spacevim |
@mb4555 thanks man, you save my day
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